sort list based on another list java

It seems what you want would be to use Comparable instead, but even this isn't a good idea in this case. Given parallel lists, how can I sort one while permuting (rearranging) the other in the same way? ', not 'How to sorting list based on values from another list?'. This tutorial covered sorting of HashMap according to Value. Is it possible to rotate a window 90 degrees if it has the same length and width? Staging Ground Beta 1 Recap, and Reviewers needed for Beta 2, Sorting a list in Python using the result from sorting another list, How to rearrange one list based on a second list of indices, How to sort a list according to another list? Key and Value can be of different types (eg - String, Integer). There are plenty of ways to achieve this. I mean swapItems(), removeItem(), addItem(), setItem() ?? Sorting a list based on another list's values - Java 16,973 Solution 1 Get rid of the two Lists. My solution: The time complexity is O(N * Log(N)). Is it suspicious or odd to stand by the gate of a GA airport watching the planes? That's right but the solutions use completely different methods which could be used for different applications. How do I make a flat list out of a list of lists? I used java 8 streams to sort lists and put them in ArrayDeques. The most obvious solution to me is to use the key keyword arg. . You get paid; we donate to tech nonprofits. then the question should be 'How to sort a dictionary? rev2023.3.3.43278. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. Stream.sorted() by default sorts in natural order. In this tutorial, we will learn how to sort a list in the natural order. O(n) look up happening roughly O(nlogn) times? Thanks for contributing an answer to Code Review Stack Exchange! Check out our offerings for compute, storage, networking, and managed databases. How To Install Grails on an Ubuntu 12.04 VPS, Simple and reliable cloud website hosting, New! We're streaming that list, and using the sorted() method with a Comparator. Sorting a List of Integers with Stream.sorted () Found within the Stream interface, the sorted () method has two overloaded variations that we'll be looking into. His title should have been 'How to sort a dictionary?'. Sort a List of Objects by Field in Java - Hire Amir We first get the String values in a list. @Richard: the keys are computed once before sorting; so the complexity is actually O(N^2). How do you ensure that a red herring doesn't violate Chekhov's gun? "After the incident", I started to be more careful not to trip over things. May be just the indexes of the items that the user changed. What do you mean when you say that you're unable to persist the order "on the backend"? Application of Binary Tree - javatpoint 1. There are a few of these built-in comparators that work with numbers (int, double, and long) - comparingInt(), comparingDouble(), and comparingLong(). The preferred way to add something to SortedDependingList is by already knowing the index of an element and adding it by calling sortedList.addByIndex(index); If the two lists are guaranteed to contain the same elements, just in a different order, you can use List listA = new ArrayList<>(listB) and this will be O(n) time complexity. If the list is greater than or equal to 3 split list in two 0 to 2 and 3 to end of list. This could be done by wrapping listA inside a custom sorted list like so: Then you can use this custom list as follows: Of course, this custom list will only be valid as long as the elements in the original list do not change. Code Review Stack Exchange is a question and answer site for peer programmer code reviews. The order of the elements having the same "key" does not matter. How can I pair socks from a pile efficiently? String values require a comparator for sorting. Mark should be before Robert, in a list sorted by name, but in the list we've sorted previously, it's the other way around. sorting the list based on another list (Java in General forum at Coderanch) @Jack Yes, like what I did in the last example. [Solved] Sorting a list based on another list's values - Java To subscribe to this RSS feed, copy and paste this URL into your RSS reader. You can create a pandas Series, using the primary list as data and the other list as index, and then just sort by the index: This is helpful when needing to order a smaller list to values in larger. How can I pair socks from a pile efficiently? I like this because I can do multiple lists with one index. 1. Here's a simple implementation of that logic. You are using Python 3. Application of Binary Tree. How To Sort the List in Java 8 - Making Java easy to learn If their age is the same, the order of insertion to the list is what defines their position in the sorted list: When we run this, we get the following output: Here, we've made a list of User objects. sorting - Java Sort particular index - Stack Overflow If you have 2 lists of identical number of items and where every item in list 1 is related to list 2 in the same order (e.g a = 0 , b = 1, etc.) vegan) just to try it, does this inconvenience the caterers and staff? How to Sort a List in Java | DigitalOcean All rights reserved. Why do academics stay as adjuncts for years rather than move around? Once you have that, define your own comparison function which compares values based on the indexes of list. The answer of riza might be useful when plotting data, since zip(*sorted(zip(X, Y), key=lambda pair: pair[0])) returns both the sorted X and Y sorted with values of X. Sorting list according to corresponding values from a parallel list If not then just replace SortedMap indexToObj by SortedMap> indexToObjList. Thanks for contributing an answer to Code Review Stack Exchange! Then you can create your custom Comparator that uses the Map to create an order: Then you can sort listA using your custom Comparator. What is the shortest way of sorting X using values from Y to get the following output? We can now eliminate the anonymous inner class and achieve the same result with simple, functional semantics using lambdas: (Employee e1, Employee e2) -> e1.getName ().compareTo (e2.getName ()); We can test it as below: Check out our offerings for compute, storage, networking, and managed databases. How to Sort a List by a property in the object. Premium CPU-Optimized Droplets are now available. Another alternative, combining several of the answers. "After the incident", I started to be more careful not to trip over things. - the incident has nothing to do with me; can I use this this way? Java List is similar to arrays except that the length of the list is dynamic and it comes in Java Collection framework. More elegant code or using some built in Java class? The solution below is simple and should fix those issues: Location of index in list2 is tracked using cur_loclist. Python. Sorting a 10000 items list 100 times improves speed 140 times (265 ms for the whole batch instead of 37 seconds) on my unit tests. Collections.sort() method is overloaded and we can also provide our own Comparator implementation for sorting rules. Getting key with maximum value in dictionary? 12 is less than 21 and no one from L2 is in between. Starting with the example input you provided: This is also known as the Schwartzian_transform after R. Schwartz who popularized this pattern in Perl in the 90s: Note that in this case Y and X are sorted and compared lexicographically. The Collections class has two methods for sorting a list: The sort() method sorts the list in ascending order, according to the natural ordering of its elements. Once you have a list of sorted indices, a simple list comprehension will do the trick: Note that the sorted index list can also be gotten using numpy.argsort(). The solution assumes that all the objects in the list to sort have distinct keys. Linear Algebra - Linear transformation question, Acidity of alcohols and basicity of amines, Is there a solution to add special characters from software and how to do it. Surly Straggler vs. other types of steel frames. Note: the key=operator.itemgetter(1) solves the duplicate issue, zip is not subscriptable you must actually use, If there is more than one matching it gets the first, This does not solve the OPs question. The solution below is simple and does not require any imports. Any suggestions? Learn the landscape of Data Visualization tools in Python - work with Seaborn, Plotly, and Bokeh, and excel in Matplotlib! Merge two lists in Java and sort them using Object property and another condition, How Intuit democratizes AI development across teams through reusability. For bigger arrays / vectors, this solution with numpy is beneficial! This is an old question but some of the answers I see posted don't actually work because zip is not scriptable. Assume that the dictionary and the words only contain lowercase alphabets. How can we prove that the supernatural or paranormal doesn't exist? Note: Any item not in list1 will be ignored since the algorithm will not know what's the sort order to use. How can I randomly select an item from a list? This comparator sorts the list of values alphabetically. For more information on how to set\use the key parameter as well as the sorted function in general, take a look at this. This trick will never fails and ensures the mapping between the items in list. If a law is new but its interpretation is vague, can the courts directly ask the drafters the intent and official interpretation of their law? Let's say we have the following code: Let's sort them by age, first. QED. A tree illustrates a hierarchical structure in contrast to other data structures such an array, stack, queue, and linked list, which are linear in nature. How to remove an element from a list by index, Sorting an array of objects by property values, String formatting: % vs. .format vs. f-string literal. How do you get out of a corner when plotting yourself into a corner.